Important Results in Context with Rotation

 

 (i) arg z = 0 represents points (non-zero) on a ray emanating from origin making an angle θ with positive direction of real axis.

result-1

(ii) arg (z-z1)= 0 represents points ( ≠3,) on ray emanating from z, making an angle θ with positive direction of real axis.

result-2

Rotation theorem:

(i) If P(z1) and Q(z2) are two complex numbers such that |z1| = |z2|, then z2=z1 e,  where θ = POQ.

(ii) If P(z1), Q(z2) and R(z3) are three complex numbers and PQR=Q, then

 

result-3

 (iii) If P(z1), Q(z2), R(z3) and S(z4) are three complex numbers and STQ= θ, then

result-4

2. amp (z) = θ is a ray emanating from the origin inclined at an angle θ to the x-axis.

3. |z-a|=|z-b| is the perpendicular bisectors of the line joining a to b.

4. The equation of a line joining z1 and z2 is given by z = z1 + t(z1-z2) where t is a real parameter.

5. z = z1 (1+it) where t is a real parameter is a line through the point z, and perpendicular to the line joining z, to the origin.

6. The equation of a line passing through z1 and z2 can be expressed in the determinant form as

determinant-form

This is also the condition for three complex numbers z, z1, z2 to b collinear.

7. The equation of a circle having centre z0 and radius p is:

         |z-z0| = p or zconjugate-z   - z0conjugate-z- conjugate-z0 - z + conjugate-z0z0 - p2 = 0 which is of the form

         zconjugate-z + conjugate-az + αconjugate-z + k = 0, k is real.

         Centre is -α  and radius =√(αconjugate-a - k)  circle will be real if αconjugate-a - k ≥ 0.

8. The equation of the circle described on the line segment joining z1 and z2 as

diameter is arg (z-z2)/(z-z2 )= ±Π/2 or (z-z1) (conjugate-z-conjugate-z2)+(z-z2 )(conjugate-z1)=0

9. Condition for four given points z1, z2, z3 and z4 to be concyclic is the number

(z3 z1)/(z3-z2 ).(z4 z2)/(z4-z1 ) should be real.

Hence, the equation of a circle through 3 non-collinear points z1, z2 and z3 can be taken as

(z-z1 )(z3-z1 )/((z-z1 )(z3-z2)) is real 

=>  (z-z2 )(z3-z1 )/((z-z1 )(z3-z2))=(conjugate-z-conjugate-z2 )(conjugate-z3- conjugate-z1)/((z-z1 )(z3-z2))

10. Arg((z-z1)/(z-z2)) = 0  represent

(i) a line segment if θ =Π

(ii) pair of ray if θ = 0

(iii) a part of circle, if 0<0<Π

11. Area of triangle formed by the points z1, z2 and z3 is

area-of-triangle-formed-by-the-points

12. Perpendicular distance of a point z0 from the line

         conjugate-az + αconjugate-z + r = 0  is |( conjugate-az0 + αconjugate-z + r )/α|α||

13. (i) Complex slope of a line conjugate-az + αconjugate-z + r = 0  w = - α/α

        (ii) Complex slope of a line joining the points z1 and z2 is w=(z1-conjugate-z2)/(z1-conjugate-z2)

        (iii) Complex slope of a line making Q angle with real axis w=l2iθ

14. Dot and Cross product

Let z1 = x1 + i y1 and z2 = x2 + i y2 be two complex numbers (vectors). The dot product (also called the scalar product) of z1 and z2 is defined by z1.z2 = |z1| |z2| cos θ

                                = x1x2 + y1y= = Re {conjugate-a1z2}

                                = 1/2{conjugate-z1z2 + z1conjugate-z2}

Where θ is the angle between z1 and z2 which lies between 0 and Π .

If vectors z1, z2 are perpendicular then z1.z2 = 0 => z1/z2 + z2/z2 = 0

i.e. sum of complex slopes = 0

The cross product of z1 and z2 is defined by

        z1 × z2 = |z1| |z2| sin θ|

                = x1y2 - y1x2

                = Im{conjugate-z1z2 }

                = 1/zi (conjugate-zz2 - z1conjugate-z2)

If vectors z1, z2 are parallel then z1 × z2 = 0 z1/z2 = z2/z2

i.e., complex slopes are equal. 

Note:

w1 and w2 are complex slopes of two lines.

(i) If lines are parallel then w1 = w2

(ii) If lines are perpendicular then w1 + w2 = 0

15. If |z-z1| + |z-z2| = K> |z1-z2| then locus of z is an ellipse focii are z1 and z2.

16. If |z-z0| =  |conjugate-az + αconjugate-z + r/2K1| then locus of z is parabola whose focus is z0 and directrix is the line

        conjugate-az + αconjugate-z + r = 0 (provided conjugate-az0+ αconjugate-z0 + r ≠ 0)

17. If |(z-z1)/(z-z2)| = k < |z1-z2|   then locus of z is a circle

18. If  then locus of z is a hyperbola, whose focii are z1 and z2.

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