Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. 26 and 91

Dear Student

Expressing 26 and 91 as product of its prime factors, we get,

26 = 2 × 13 × 1
91 = 7 × 13 × 1

Therefore,
LCM (26, 91) = 2 × 7 × 13 × 1 = 182

And HCF (26, 91) = 13 Verification
Now, product of 26 and 91= 2366

And Product of LCM and HCF = 182 × 13 = 2366

Hence, Proved

Thanks