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If the polynomial p(x)=x5+ax4+bx3+cx2+dx+e has five different intercepts. One of which is(0,0). Then find which of the coefficient cannot be 0.

Gopesh , 5 Years ago
Grade 9
anser 1 Answers
Arun

Last Activity: 5 Years ago

Clearly, since $(0,0)$ is an intercept, $e$ must be $0$. But if $d$ was $0$, $x^2$ would divide the polynomial, which means it would have a double root at $0$, which is impossible, since all five roots are distinct.
hence d can't be zero

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