Barium chloride reacts with aluminum sulphate to give aluminum chloride and precipitate of barium sulphate.

Hint: Barium chloride stands forBaCl2, aluminum sulphate stands for Al2(SO4)3, barium sulphate stands for BaSO4 and last aluminum chloride stands for AlCl3. Arrange them, chemical reactions and balance them. The symbolic representation of barium is Ba. The symbolic representation of chloride is Cl. The symbolic representation of aluminum is Al. The symbolic representation of sulphate is SO4. Complete step-by-step answer: Barium chloride is represented as BaCl2 barium has oxidation state and chlorine has oxidation state. Therefore 1 barium combines with 2 chlorides. Aluminum sulphate is represented by Al2(SO4)3 as aluminum has oxidation state and sulphate has oxidation state. So, 3 aluminum reacts with 3 molecules of sulphate. When barium chloride reacts with aluminum sulphate it gives aluminum chloride and barium sulphate as a product. Barium sulphate is represented as BaSO4 barium has oxidation state and sulphate has oxidation state. Therefore 1 barium combines with 1 Sulphur. Aluminium chloride is represented by AlCl3 as aluminum has oxidation state and chlorine has oxidation state. So, 1 aluminum reacts with 3 chlorines. So overall reaction is: BaCl2+Al2(SO4)3→AlCl3+BaSO4 Now, balancing the equation as the number of elements as they are not equal on both sides. So the balanced equation is: 3BaCl2+Al2(SO4)3→2AlCl3+3BaSO4 Now labeling the physical state of each reactant and product: 3BaCl2(aq)+Al2(SO4)3(aq)→2AlCl3(aq)+3BaSO4(s) It is given that barium sulphate precipitates therefore it is solid and others are aqueous in their physical state. Note: Chemical equation is written by the chemical name of each compound present as reactant or product arranging them in an equation followed by balancing of equation as stoichiometry should be the same. After balancing the equation, the physical state of each reactant and product is written.