In the dihybrid cross, the two parental genotypes are AABB and aabb. The genotype of all F1 plants is AaBb. What phenotypes ration will be observed in the F2 Generation?A) 8:4:2:1B) 1:1:1:1C) 4:2:2:1D) 1:2:2:1E) 9:3:3:1

In a dihybrid cross where the parental genotypes are AABB and aabb, the F1 generation will all be heterozygous for both traits, resulting in the genotype AaBb. To determine the phenotypic ratio in the F2 generation, we need to consider the Mendelian inheritance patterns for two independently assorting genes.

When two heterozygotes (AaBb) are crossed, the F2 generation will exhibit the following genotypes based on a 9:3:3:1 phenotypic ratio, which is typical for dihybrid crosses where both genes assort independently:

Dominant for both traits (A_B_):

Possible genotypes: AABB, AABb, AaBB, AaBb
Total combinations: 9 (out of 16)
Dominant for the first trait and recessive for the second (A_bb):

Possible genotypes: AAbb, Aabb
Total combinations: 3 (out of 16)
Recessive for the first trait and dominant for the second (aaB_):

Possible genotypes: aaBB, aaBb
Total combinations: 3 (out of 16)
Recessive for both traits (aabb):

Possible genotype: aabb
Total combinations: 1 (out of 16)
Thus, the phenotypic ratio observed in the F2 generation of this dihybrid cross will be:

9:3:3:1

Therefore, the correct answer is:

E) 9:3:3:1