The number of sigma and pi bonds in C2H2 is: (A) 0 and 4 (B) 2 and 2 (C) 3 and 2 (D) 4 and 2

To determine the number of \(\sigma\) and \(\pi\) bonds in \( \text{C}_2\text{H}_2 \) (ethyne or acetylene), let's analyze its structure:

1. **Structure of \( \text{C}_2\text{H}_2 \):**
- Ethyne (acetylene) has a linear structure.
- The molecular formula is \( \text{C}_2\text{H}_2 \), which means there are 2 carbon atoms and 2 hydrogen atoms.

2. **Bonding in Ethyne:**
- Each hydrogen atom forms a single bond with a carbon atom.
- The two carbon atoms are connected by a triple bond.

3. **Counting Bonds:**
- **Single Bonds:**
- Each carbon-hydrogen bond is a \(\sigma\) bond.
- There are 2 \(\sigma\) bonds between carbon and hydrogen.
- **Triple Bond between Carbons:**
- A triple bond consists of one \(\sigma\) bond and two \(\pi\) bonds.

4. **Summarizing the Bonds:**
- **\(\sigma\) Bonds:**
- 2 \(\sigma\) bonds between C and H.
- 1 \(\sigma\) bond within the C-C triple bond.
- Total \(\sigma\) bonds = \(2 + 1 = 3\).
- **\(\pi\) Bonds:**
- 2 \(\pi\) bonds within the C-C triple bond.
- Total \(\pi\) bonds = 2.

Therefore, the number of \(\sigma\) and \(\pi\) bonds in \( \text{C}_2\text{H}_2 \) is \( 3 \) and \( 2 \), respectively.

So, the correct answer is: **(C) 3 and 2**.