Pawan Prajapati
Last Activity: 3 Years ago
Determining the divisibility of a dividend is easy if the divisor is broken into its factors. If we try to check for divisibility by 45 itself, it might lead to a complex calculation. So, it is advised to break 45 into its prime factors.
Complete step-by-step answer:
Here, we have to check the divisibility of 25110 by 45.
And it is easy to determine divisibility with divisor’s prime factors, thus prime factors of divisor 45 is
45=32×5×1
Thus, prime factors of 45 are: 3,5,1... (1)
Now, to determine the divisibility of 25110 by 45, we have to check its divisibility with 3,5,1, i.e.,
Divisibility rules of 3 and 5 will be checked on 25110, as it is already divisible by 1.
Now,
Divisibility rule of 3 is, if sum of all the digits of dividend is divisible by 3 or not, if it is divisible by 3 then the whole dividend is said to be divisible by 3... (2)
Similarly, divisibility rule of 5 is, if the last digit of dividend is either 0 or 5, then dividend is said to be divisible by 5... (3)
From combining equation (2) and (3), we can say that
A dividend is said to be divisible by 45, only if it is divisible by 3 and 5.
Thus, applying divisibility rule of 3 on 25110 from equation (2), we get
25110→(2+5+1+1+0)=9, which is divisible by 3
And applying divisibility rule of 5 from equation (3), we get
25110→ last digit is 0, hence it is also divisible by 5
Thus, we can say that 25110 is divisible by 3 and 5.
Hence, 25110 is divisible by 45.
Note: An easiest way to solve such problems is direct division of dividend through divisor. If the remainder comes out to be 0 then it can be said that dividend is divisible by divisor.