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consecutive numbers whose product exceeds the square of the smaller by 7 ...whnat”s the answer ???

Ridhiksha hemanth mulya , 9 Years ago
Grade 10
anser 8 Answers
Ridhiksha hemanth mulya

Last Activity: 9 Years ago

?????
 

noogler

Last Activity: 9 Years ago

7,8

noogler

Last Activity: 9 Years ago

consecutive no. be x,x+1
given x(x+1)=x2+7..........solve it

noogler

Last Activity: 9 Years ago

approve if usefull!!!!!!!!!!!

VAISHNAVI BATHINA

Last Activity: 9 Years ago

7,8

V. Harshit -

Last Activity: 9 Years ago

7,8
x(x+1)=x^2+7
x^2+x-x^2=7
x=7
x+1=8
x and x+1are the 2 nos

Dweepayan Biswal

Last Activity: 7 Years ago

7,8

vijay kale

Last Activity: 7 Years ago

Let the numbers be x and x+1.Therefore (x+1)x=x^2+7x^2 +x=x^2+7×=7×+1=87,8 are the required number

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