Saurabh Singh
Last Activity: 10 Years ago
angle APB =60
as op is at centre of square so clearly PA=PB
so angle PAB=anglePBA
and as angle APB=60 so we can see that in triangle APB angle PAB=angle PBA=60
hence its an equilateral triangle thus making AP=PB=AB=b
now lets see triangle AOB
O is centre of square so angle AOB=90
giving us AO=OB=AB/root(2)
so AO= b/root(2)
now in triangle AOP right angled at O
AO2+OP2=PA2
b2/2+ h2= b2
h2=b2/2
so answer is option (B)
Thanks & Regards
Saurabh Singh,
askIITians Faculty
B.Tech.
IIT Kanpur