Gladan Delwin Dsouza
Last Activity: 3 Years ago
It’s pretty simple
First, we find the length of CE :
Since Triangle AEC is a Right-angled triangle we use Pythagoras theorem
12²+ CE² = 13²
CE²=25 Therefore CE = 5cm
Now we find length BE:
AE-DC = BE (as they are opposite sides of the parallelogram)
12-10 = 2 Therefore BE = 2cm
Hence we use Pythagoras theorem again in triangle BEC
to find Hypotunuse side BC:
5²+2² = BC²
BC² = 29
BC = 5.3851cm
Hence area of the given figure:(Height × Base)
AB × BC
10cm × 5.385cm = 53.851cm²