Flag AIIMS MBBS> a rod rotates about point A .The rod is r...
question mark

a rod rotates about point A .The rod is released from rest in the horizontal position so that it rotates about point A.[moment of inertia about point A =ml^2/3].find initial angular acceleration. [in the question how can we equate torque at A and torque due to mg. torque atA is 0.]

liza , 5 Years ago
Grade 11
anser 1 Answers
chetan jangir

Last Activity: 5 Years ago

Hey Liza I hope you know how to calculate torque ,Torque due to force about a point is Forcein perpendicular direction *(into)its perpenidular distance about that point (here A) SO we know equation of rotation motion torque net= I(moment of inertia)*angular acceleration .Mg*L/2=Ml^{^{2}}/3\alpha (here \alpha= angular acceleration) Calculating \alpha=3g/2l
Here at A a tension acts but it’s torque is zero as it’s perdicular distance is zero and also it passes through A

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...

question mark
most scoring topics for neet?for all the subjects : chemisrtry,biology and physics
AIIMS MBBS
0 Answer Available

Last Activity: 2 Year ago(s)