a rod rotates about point A .The rod is released from rest in the horizontal position so that it rotates about point A.[moment of inertia about point A =ml^2/3].find initial angular acceleration. [in the question how can we equate torque at A and torque due to mg.
liza , 5 Years ago
Grade 11
2 Answers
Arun
Last Activity: 4 Years ago
Dear student
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Vikas TU
Last Activity: 4 Years ago
Dear student Question is not clear Please attach an image, We will happy to help you Good Luck Cheers
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