a solid sphere of mass M and radius r rolls inside hemispherical bowl of radius Rwithout slipping from the rim of a hemispherical cup so that it rolls along the surface. If the rim of the hemisphere is kept horizontal.normal reaction exerted by the bowl on the sphere at the bottom point of the hemisphere is[ please provide required steps]
liza , 5 Years ago
Grade 11
2 Answers
Arun
Last Activity: 4 Years ago
According to Energy Conservation:-
mgR=1/2 (I of disc)(omega)² + 1/2 mv²
mgR=1/2 (mR²/2)(v/R)² + 1/2mv²
2mgR= 3/2 mv²
4/3 mg = v²/R
4/3 mg = a
Let Normal force be N
N - mg = ma
N - mg = 4/3 mg
N = 4/3 mg + mg
N = 7/3 mg
Vikas TU
Last Activity: 4 Years ago
Dear student
Total normal force =mg+mv^2/R−r Ag∈,mg(R−r)=1/2Iω2 + 1/2mv2 mg(R−r)=1/2x2/5mv^2+1/2mv^2
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