Arun
Last Activity: 4 Years ago
We will analyse this problem from the reference frame of elava tor. Total buoyant force on the block is
FB=(2 5Vρ2+35 Vρ1)(g+a)FB=(25Vρ 2 +35V ρ1)(g+a)
From the condition of equilibrium
FB=T+Vd(g +a)FB=T +Vd(g+a)
⇒T=F B−V d(g+a)=(g+a)V[ 25ρ 2+3 5ρ 1−d]⇒T=FB -Vd(g+a)=(g+a)V[25 ρ2+35ρ1- d]
=15×10−3[25×1500+35×1000−800]=6N