In a oscillatory system, the amplitude of motion is 5m and the time period is 4s. The time taken by the particle for passingbetween points which are at the distances of 4m and 2m from the centre and on the same side of it will be ?
vinushree , 5 Years ago
Grade 12th pass
1 Answers
Arun
Last Activity: 5 Years ago
y = A sin ωt
ω= 2π/T , T is the period.
When y = 4m
4 = 5 sin ( 2π/4 ) *t1 =5 sin 1.571 t1
sin 1.571 t1 = 0.8
1.571 t1 =0.9272 radian
t1 = 0.590 s
When y = 2m
2 =5 sin 1.571 t2
t2 = 0.2619
Time difference is 0.59 - 0.26 = 0.33 s
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