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The number of moles of oxygen in one litre of air containing 21% oxygen by volume under standard conditions are

fanna , 5 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 5 Years ago

Assuming ideal gas.

21% oxygen of 1 L=0.21 L oxygen

PV=nRT

( 1 atm)*(0.21 lit) = (no. of moles of oxygen)*(0.0821)*(273.15 K)

(no. of moles of oxygen) = 0.00936429168 mols

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