AKASH GOYAL AskiitiansExpert-IITD
Last Activity: 14 Years ago
Dear Jayati
As N is divisible by 12 or I can say divisible by both 3 and 4.
For divisibility by 3, sum of digits shuld be divisible by 3
sum of digits=36+a
so a can be 0,3,6,9
For divisiblity by 4 last two digits shold be divisible by 4
So a can be 0,2,4,6,8
To be divisible by both a=0 or 6
hence 2 is the answer
All the best.
AKASH GOYAL
AskiitiansExpert-IITD
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