Askiitians Expert Soumyajit IIT-Kharagpur
Last Activity: 14 Years ago
Dear Nehal Wani,
Ans: Do you know the log seriess? These are
log(1+x)=x-x²/2+x³/3- ...............
log(1-x)=-(x+x²/2+x³/3+...............)
In your problem there are 2 log series those are
log(1-p) && log(1-q)
where p=x/(x+1) q=1/(x+1);
Hence the sum is=log(1-q) - log(1+q)
=log[1-x/(x+1)]-log[1-1/(x+1)]
=log[x/(x+1)]-log[1/(x+1)]
=logx
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Regards,
Askiitians Experts
Soumyajit Das IIT Kharagpur