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Find the number of Positive divisors of the number(2010)^2 are ?

A Sai teja , 6 Years ago
Grade 12
anser 2 Answers
Deepak Kumar Shringi

Last Activity: 6 Years ago

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Samyak Jain

Last Activity: 6 Years ago

First of all factorise 2010 in prime numbers.
So 2010 = 2* 5* 3* 671  
There is one 2 in the prime factorisation of 2010. So we have two choices of selecting 2.
First, to take it and second not to take it.
Similarly we have two choices each of selecting of 5, 3, 67;
either to take the number or to skip it.
\therefore No. of divisors = 2 * 2 * 2 * 2 = 16
The anwer contains different combination of numbers. 
One selection is not to take any of the mentioned prime numbers.
In this case, we indirectly took 1 as a divisor of 2010.

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