In a ?ABC, if cos A / a = cos B / b = cos C / c and the side a = 2, then area of the triangle is
Manish , 10 Years ago
Grade 12
1 Answers
bharat bajaj
Last Activity: 10 Years ago
cos A / a = cos B / b = cos C / c cos A / (2R sin A) = cos B / (2R sin B) = cos C / (2R sin C) cot A = cot B = cot C A = B = C ?ABC is equilateral. Area == Thanks
Bharat Bajaj
askiitians faculty
IIT Delhi
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