SHAIK AASIF AHAMED
Last Activity: 10 Years ago
Hello student,
Please find the answer to your question below
Iam explaining every step again here
Let d be the common difference in AP
So d=a2-a1=a3-a2=a4-a3=........=a2m-a2m-1
Now a12-a22+..............+a2m-12-a2m2
=(a1+a2)(a1-a2)+.............+(a2m-1+a2m)(a2m-1-a2m)
= -d(a1+a2+.........+a2m) since a1-a2=a2-a3=.....=a2m-1-a2m=-d
=-d(2m/2)(a1+a2m)
[since sum to n terms =n/2(a+l) here there are 2m terms where l=last term]
=-dm(a12-a2m2)/(a1-a2m)
=dm(a12-a2m2)/(a2m-a1)
=(m/(2m-1))[a12-a2m2] since [a2m=a1+(2m-1)d which is nth term formula]
I hope you will understand this now