Rishi Sharma
Last Activity: 4 Years ago
Dear Student,
Please find below the solution to your problem.
Y⊆X,Z⊆X
Let a∈X, then
a∈Y,a∈Z.....(1)
a∈/Y,a∈Z.....(2)
a∈Y,a∈/Z.....(3)
a∈/Y,a∈/Z.....(4)
We require Y∩Z=φ
Thus, for a, equation (1),(2) and (3) can satisfy Y∩Z=φ
Therefore,
Y∩Z=φ has 3 options.
Thus,
No. of required possibilities for 5 elements of X = 3^5
Thanks and Regards