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Please let me know the answers for 11, 12 and 13 questions in passage 1

RAHUL SANAPALA , 3 Years ago
Grade 9
anser 1 Answers
Abhishek Singh

Last Activity: 3 Years ago

Clearly
\begin{align*} f(x) &= \sqrt{\frac{1+Cos2x}{2}}\\ &=\sqrt{Cos^2x} \\ &= |Cos(x)| \end{align*}
Now Draw the graph of |Cos(x)| and check the injectivity by Horizontal line test and see it is injective for option (C)
 
12) f(x) = |x|, Clearly it becomes onto for optiond (D) by graph 
13) For explicitly writing the function, check that 
     if x is integer f(x) = [x] + [-x] = x+ (-x) = 0
     if x is non integer f(x) = [x] + [-x] = [x] + (-[x] -1) = -1 
 
 f(x) \begin{cases} 0& \text{ if } x= integer\\ -1&\text{ if } x= non-integer \end{cases}
Its range is {0,-1} which is not in options
 
 

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