Nicho priyatham
Last Activity: 9 Years ago
- by multiplyng Nr and Dr with (1-2isin(x/2)) and equating imagnary part to zero we get the equation
2sin2(x/2)+sinx +tan(x/2)=0
- 1-cosx +sinx+tanx=0
- 1+tanx=cosx-sinx
- (cosx+sinx)/cosx=cosx-sinx
- (cosx+sinx)/(cosx-sinx)=cosx
by commponnendo dividendo we get
since RHS is always positive both should LHS RHS must be zero so
- tan(x/2)=0 and tanx=0
- x=2n(pie)