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Last Activity: 7 Years ago
case 1 :- number does not contain 0.
from 1, 2, 3, 4, 5, 6, 7, 8, 9
choose 5 digits by
ways.
one number is largest which occupies middle place. arrange rest four numbers in 4! ways. thus
X 4! =3024.
case 2 :- contains 0
choose other four numbers from 1,2,3,4,5,6,7,8,9 in
ways. largest occupies third position.
no of ways numbers can be arranged = 3 X 3 X 2 X 1 =18
ways =
X 18 = 2268
therefore our answer is 3024 + 2268 = 5292