Deepak Kumar Shringi
Last Activity: 6 Years ago
To find equation of normal in slope form simply differentiate the curve find dy/dx that is slope of tangent now slope of normal is -dx/dy and a point must be given in question on which normal has to be drawn use this point to find equation of line in slope form
y-y1=m(x-x1)
To find in parametric form replace (x1y1) by parameters according to the curve
Thanks and Regards
deepak shringi
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