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Let V be the vertex and L be the latusrectum of the parabola x2 = 2y + 4x – 4. Then the equation of the parabola whose vertex is at V, latusrectum is L/2 and axis is perpendicular to the axis of the given parabola.(a) y2 = x – 2(b) y2 = x – 4(c) y2 = 2 – x(d) y2 = 4 – x

Hrishant Goswami , 11 Years ago
Grade 10
anser 1 Answers
Amit Saxena

Last Activity: 11 Years ago

(AC)

 

Sol.     x2 – 4x = 2y – 4

 

            x2 – 4x + 4 = 2y – 4 + 4

 

            (x – 2)2 = 2y

 

            vertex of parabola (2, 0) and length of latusrectum = 2

 

length of latusrectum of the required parabola = 1

 

\         equation of the required parabola is

 

            (y – 0)2 = + 1(x – 2)

 

            y2 = x – 2 or y2 = 2 – x

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