Hi sir,,please post the solution of the problem,Q:The equation of the plane bisecting the acute angle between the planes 2x-y+2z+3=0 and 3x-2y+6z+8=0 is.........Ans. 23x-13y+32z+45=0

Dear Tapasranjan

for acute angel bisector

(2x-y+2z+3)√(2²+1²+2²)= - ( 3x-2y+6z+8)/√(3²+2²+6²)

7(2x-y+2z+3) =-3(3x-2y+6z+8)

23x-13y+32z+45=0

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