Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear Tapasranjan
concept in this question is that length of perpendicular from the center of circle to given line will be constant
not lets center of circle is ( h,k)
so |(h-1)cosθ +(k-1)sinθ -1|/ √(cos2θ +sin2θ) = constant
|(h-1)cosθ +(k-1)sinθ -1| = constant
L H S to be constant only for h=1,k=1
so center will be (1,1) and radius of the circle = 1
so equation of circle = (x-1)2 + (y-1)2 =1
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