Lakshay Kumar
Last Activity: 7 Years ago
Let the equation of the general form of the required circle be x^2 + y^2 + 2gx + 2fy + c = 0 ……………. iAccording to the problem, the above equation of the circle passes through the points 1, 1, 2, -1 and 3, 2. Therefore,1 + 1 + 2g + 2f + c = 0 2 + 2g + 2f +c = 0……………. ii4 +1 + 4g - 2f+ c = 0 5 + 4g - 2f + c = 0……………. iii9 + 4 + 6g + 4f + c = 0 13 + 6g + 4f + c = 0……………. ivOn solving ii and iii, and iii and ivWe obtain c = 4, g = -5/2 and f = -1/2Substituting the values of g, f and c in i, we obtain the equation of the required circle as x^2 + y^2 - 5x - y + 4 = 0