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Product of the perpendiculars from (-1,2) to the pair of lines x2+kxy+3y2=0 is 4/√5,then k is

Pawan joshi , 6 Years ago
Grade 12th pass
anser 1 Answers
Ajeet Tiwari

Last Activity: 4 Years ago

hello student
the value of k whenProduct of the perpendiculars from (-1,2) to the pair of lines x^2+kxy+3y^2=0 is 4/√5,then k is as solved in picture642-1915_upload 13.png
hope it will help
thankyou

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