Flag Branch Ranking of IIT> (a) Two plates (20 cm x 3.0 cm) are separ...
question mark

(a) Two plates (20 cm x 3.0 cm) are separated by a 1.0 mm air gap forming a capacitor. Assume dielectric constant () for air is 1.000. The capacitor is connected to a 12 V battery. i) Determine the capacitance of the parallel plate capacitor. ii) What is the charge on each plate? (b) Three particles of charge 50 C, 27 C and –70 C are placed in a straight line with the 27 C charge in the middle and the 50 C charge to its left. The charge in the middle is 0.30 m from each of the other two charges. Calculate the magnitude and direction of net force on the 27 C charge due to the other two charges.

Mayank , 4 Years ago
Grade 12th pass
anser 2 Answers
Arun

Last Activity: 4 Years ago

C= 
d
ϵ 
o
​ 
 A
​ 
 
According to the values given C=1.8×10 
−11
 F
Now Q=CV
Hence charge on the positive plate will be 1.8×10 
−9
 C
(a) Dielectric constant, k = 6
C=1.8×10 
−11
  F
new capacitance, C 
 =kC=108 pF
V=100volts
 =V×C 
 =1.08×10 
−8
  C
V remains the same.
 
(b) C 
 =kC=6×1.8×10 
−11
 =108pF
q remains the same.
q=1.8×10 
−9
  C
 =q/C 
 =16.67 V

Vikas TU

Last Activity: 4 Years ago

Dear student 
The above explanation is not properly explained 
Please ignore this 
We are sorry for inconvenience.
Good Luck 
Cheers 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...