Last Activity: 13 Years ago
f(x) = {ax - 1}/{xn(ax + 1)} ......................1
f(-x) = {a-x - 1}/{(-x)n(a-x + 1}
f(-x) = {1-ax}/{xn(1 + ax)}(-1)n
f(-x) = {-1/(-1)n} {f(x)} ...................2
f(x) is even function if f(x) = f(-x)
for this condition -1/(-1)n should be 1
n = 1 , 3 , 5 .........
n should be odd integer
......
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 2 Year ago(s)