Last Activity: 15 Years ago
for y=2,we have : 2+5fx = fx+5+f2x
4fx=3+f2x
putting x=0 gives f0=1
x=1 gives f0=2
x=2 gives f4=17
which clearly indicates fx=x2 + 1
limit x->2 fx is 5
option A
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regards
Ramesh
Hi,
Since fx is a polynomial, Hence it is continuous, therefore lim x→2 fx = f2 = 5
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