Flag Differential Calculus> Limits and functions
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If fxfx is a polynomial satisfying 2+fx2+fx fyfy = fxfx ++ fyfy ++ fxyfxy for all real x and y and f2f2 = 55. Then lim x→22 fxfx isa5isa5 b25b25 c4c4 dnonnednonne of these

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Tushar Watts , 15 Years ago
Grade 12
anser 2 Answers
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Ramesh V

Last Activity: 15 Years ago

for y=2,we have : 2+5fx = fx+5+f2x

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4fx=3+f2x

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putting x=0 gives f0=1

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x=1 gives f0=2

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x=2 gives f4=17

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which clearly indicates fx=x2 + 1

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limit x->2 fx is 5

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option A

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regards

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Ramesh

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Askiitian.Expert Rajat

Last Activity: 15 Years ago

Hi,

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Since fx is a polynomial, Hence it is continuous, therefore lim x→2 fx = f2 = 5

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