Badiuddin askIITians.ismu Expert
Last Activity: 15 Years ago
Dear chilukuri
case 1 x>=0
2x+2|x|>2(2)1/2
2x+2x>2(2)1/2
2x>(2)1/2
x>=1/2
case 2 x<0
2x+2|x|>2(2)1/2
or 2x+2-x>2(2)1/2
or 22x+1>22x(2)1/2
simplify
(2x -21/2 -1)((2x -21/2 +1)>0
first bracket is always negative so second bracket should also be negative
(2x -21/2 +1)<=0
2x <=21/2 -1
xln2 <=ln(21/2 -1)
x<=ln2(21/2 -1)
so final solution
x<=ln2(21/2 -1) and x>=1/2
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best.
Regards,
Askiitians Experts
Badiuddin