Badiuddin askIITians.ismu Expert
Last Activity: 14 Years ago
Dear Jayati
y2=4ax
x2=4by
solve the curve for point of intersection
x1 =4(ab2)1/3
y1 =4(ba2)1/3
now slope of tangent at these points are
slope on curve y2=4ax , m1 =2a/y1
slope on curve x2=4by , m2 =x1/2b
m1 * m2 =-1
ax1/by1 =-1
a4(ab2)1/3/b4(ba2)1/3=-1
a2 +b2 =0
which is not possible
so option d is correct
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