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I did a mechanics sum in which I considered (dx)^2=0 exactly. My friend did it without calculus and got the same answer. So, does it mean that (dx)^2 is exactly 0? If so, how?The sum was to find the distance moved under a closed path described by the x-co-ordinate as a function of time:x(t)=bt(1-at)

Rahul Bordoloi , 7 Years ago
Grade 10
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