Please solve the ques in the attachment................................
Pawan joshi , 5 Years ago
Grade 12th pass
1 Answers
Arun
Last Activity: 5 Years ago
Dear Pawan
lim(x→0) (1cosec2x+2cosec2x+...+ncosec2x)sin2x = ncosec2xsin2x[(1/n)cosec2x+(2/n)cosec2x+....+1]sin2x = n[(1/n)cosec2x+(2/n)cosec2x+....+1]sin2x = n (as r/n ∞→0)(further as n does not tend to ∞, so we dont have (→0)infinite no. of times. so all the terms can be assumed to be zero)
Hence option D is correct.
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