Badiuddin askIITians.ismu Expert
Last Activity: 15 Years ago
Dear Kushal
we know that "number of permutation of n distinct thing taken r at a time is
nPr=n!/(n-r)!=n(n-1)(n-2)(n-3)............(n-(r-1))
put r=n
nPn=n(n-1)(n-2)(n-3)...........3.2.1
n!/(n-n)! =n!
n!/0!=n!
0!=1
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