Arun
Last Activity: 4 Years ago
Suppose mass of rod be M, and at a certain time, it makes angle θ with the vertical.
The only force acting on the rod is its own weight, which provides a torque about point O,
τ=Mg
2
L
sinθ
Moment of inertia of rod about I is:
I
C
=
3
ML
2
During rotation, we have:-
τ=Iα, and for point O:
Mg
2
L
sinθ=
3
ML
2
α
⇒α=
2L
3gsinθ
Hence centre of mass has an acceleration:
a
CM
=Rα, where R=
2
L
gives a
CM
=
4
3
gsinθ.