If 5 to the power x - 1 + 5 to the power x + 5 to the power x + 1 is equal to 775, find the value of x where X is a positive integer options are first option one second option 3 third option to fourth and last option 4 please answer this question

5^x-1 + 5^x + 5^x+1=7755^x(5^-1 + 1 +5^1)=7755^x(31/5)=7755^x=775*5/315^x=5^3 //both sides of 5 will cancel outx=3

5^x-1 + 5^x + 5^x+1=775......5^x(5^-1 + 1 +5^1)=775.......5^x(31/5)=775.......5^x=775*5/31.......5^x=5^3 //both sides of 5 will cancel outx=3