Raghulal Prajapati
Last Activity: 6 Years ago
according to ur question all the resistances are in parallel to each other .
so the solution is :
as we know W= V2/R ------> R= V2/W
so resistance for kettle is : 220*220/800= 121/2 ohm
resistance for (1) bulb is : 220*220/100= 484 ohm
as all are in parallel so net resistance is 1/resistance of kettle +3/resistance of bul = 1/ equivalent resistance
so equivalent resistance= 44 ohm
so current in circuit = v/R = 220/44= 5 ampere.
thank u.
