Tushar Nandanwar
Last Activity: 6 Years ago
Power consumption =10 units5hour=10 units 1 hour=2kW=2000J/sSo I=P/V=2000/220=9.09 AA Power loss in copper wire=I*I*R=I*Iρl/APower loss in copper wire=9.09×9.09×1.7×10−8×10π×(10−3)2=4.47J or 4.472000×100%=0.22% Power loss in aluminium wire=I*IR=I*Iρl/APower loss in copper wire=9.09×9.09×2.7×10−8×10π×(10−3)2=7.1J or 7.12000×100%=0.355%