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please see the image..

MOHAMMAD AFROZ , 9 Years ago
Grade 12
anser 1 Answers
Shivam Chopra

Last Activity: 9 Years ago

Here, 3Ω & 6Ω are parallel. So, equivalent resistance = 2Ω
Now, 12Ω & 4Ω are parallel, So, equivalent resistance = 3Ω
Now, 2Ω & 3Ω are in series. So, total = 5Ω
Voltage = 60V. So, current = 12 A.
Now, for the 1st set of 3Ω & 6Ω,
Potential difference = 2/(2+3) *60 = 24V
So, for 3Ω, current = 24/3 = 8A.
For 6Ω, current = 24/6 = 4A.
Now, for 2nd set of 12Ω & 4Ω
Potential difference = 3/(2+3) * 60 = 36V
For 12Ω, current = 36/12 = 3A.
For 4Ω, current = 36/4 = 9A.
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