A particle moves in a circle of diameter 1.0 cm under the action of a magnetic field of 0.40 T. An electric field of 200 V/m makes the path straight. Find the charge/mass ratio of the particle.
Hrishant Goswami , 10 Years ago
Grade 10
1 Answers
Jitender Pal
Last Activity: 10 Years ago
Sol. r = 0.5 cm = 0.5 × 10^–2 m
B = 0.4 T, E = 200 V/m
The path will straighten, if qE = quB ⇒ E = rqB * B/m [∴ r = mv/qB]
⇒ E = rqB^2/m ⇒ q/m E/B^2r = 200/0.4 *0.4 * 0.5 * 10^-2 = 2.5 * 10^5 c/kg
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on Electromagnetic Induction