Aditi Chauhan
Last Activity: 10 Years ago
Sol. L = 1.0 H, R = 20 Ω , emf = 2.0 V
Τ = L/R = 1/20 = 0.05
i base 0 = e/R = 2/20 = 0.1 A
i = i base 0 (1 – e^-t ) = i base 0 – i base 0 e^-t
⇒ di/dt = di base 0/dt (i base 0 x – 1/τ x e^-t/τ) = i base 0 / τ e^-t/τ
So,
a) t = 100 ms ⇒ di/dt = 0.1/0.05 x e^-0.1/0.05 = 0.27 A
(b) t = 200 ms ⇒ di/dt = 0.1/0.05 x e^-0.2/0.05 = 0.0366 A
(c) t = 11 s ⇒ di/dt = 0.1/0.05 x e^-1/0.05 = 4x 10^-9 A