Navjyot Kalra
Last Activity: 10 Years ago
Sol. V base A = V base B = V base C
For A, the process is isothermal
P base AV base A = P base A’V base A’ ⇒ P base A’ = P base A V base A/ V base A’ = P base A * ½
For B, the process is adiabatic,
P base A(V base B)^γ = P base A’(V base B)^γ = P base B’ = P base B(V base B/V base B’)^γ = P base B * (1/2)^1.5 = P base B/2^1.5
For, C, the process is isobaric
V base C/T base C = V base C’/T base C’ ⇒ V base C/T base C = 2V base C’/T base C’ ⇒ T base C’ = 2/T base C
Final pressures are equal.
= P base A/2 = P base B/2^1.5 = P base C ⇒ P base A : P base B : P base C = 2 : 2^1.5 : 1 = 2 : √2 : 1