What length of a copper wire of cross-sectional area 0.01 mm^2 will be needed to prepare a resistance of 1 kΩ? Resistivity of copper = 1.7 × 10^-8 Ω-m.
Simran Bhatia , 10 Years ago
Grade 11
1 Answers
Kevin Nash
Last Activity: 10 Years ago
Sol. f base cu = 1.7 * 10^–8 Ω-m
A = 0.01 mm^2 = 0.01 * 10^–6 m2
R = 1 KΩ = 10^3 Ω
R = fℓ/a
⇒ 10^3 = 1.7 * 10^-8 * ℓ/10^-6
⇒ ℓ = 10^3/1.7 = 5.08 * 10^3 m = 0.6 km.
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