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When 11.00 × 101210^12 electrons are transferred from one conductor to another, a potential difference of 1010 V appears between the conductors. Calculate the capacitance of the twoconductortwo-conductor system.

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Hrishant Goswami , 10 Years ago
Grade 10
anser 1 Answer
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Deepak Patra

Last Activity: 10 Years ago

Sol. Given thatrnNumber of electron = 1 × 10^12rnNet charge Q = 1 × 10^12 × 1.6 × 10^–19 = 1.6 × 10^–7 Crn∴ The net potential difference = 10 L.rn∴ Capacitance – C = q/v = 1.6 * 10^-7/10 = 1.6 * 10^-8 F.

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