This question is for aspirants:The electric field strength depends onlyon the x and y coordinates according to the lawwhere aisa constant, i and j are unit vectorsalong x and y axes respectively. Find the flux of thevector E through a sphere of radius R with itscentre at the origin of coordinates.its a simple problem.

 respected sir

 i m little confused about this question. actually electric field is 2-d only but for anwsering flux we have to consider total surface area.

well i am presenting my solution:;

E at (R,0,0) is a/R. similarly E at (0,R,0) is also a/R. so this could be taken as the a simple charge system such that a charge q is placed at origin.

now

kq/R^2 =a/R

thus q=1/k* a*R

so flux is 4pi*a*R.

i am not sure this is right . if u find it wrong plz correct it.

pleeeez tell d answer b'coz the answer coming is radius or size dependent which is not possible